Question 32: Which of the functions below has exactly 2 extremes?

+ A. This is a function of order 3 with . Therefore, the function has two extremes.

+ B. The function \(y = {x^4} + 3{x^2} + 2\) has 1 extreme.

+ C. Yes \(y’ = \frac{{2{x^2} + 1}}{{3{x^2}}} > 0\forall x \in R\). Therefore, this function is covariate on each of its defined intervals.

This function has no extremes.

+ D. Yes \(y’ = 2017.6{x^5} + 2016.4{x^3}\). Consider \(y’ = 0 \Leftrightarrow x = 0\)

So this function has exactly 1 extreme.

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